Math, asked by navdeepsingh73, 1 month ago

A fruit vendor sold 5 oranges for ruppee4 gaining 40%. Find CP and SP of one orange.​

Answers

Answered by Abhinav3583
0

Answer:

S.P. of 4 oranges = Rs. 3

S.P. Of 1 orange = Rs. 3/4, gain = 50 %

S.P. = (C.P. × 150)/100

∴ C.P. of 1 oranges = (100 × S.P.)/(100 + 50)

= (100 × ¾)/150 = 75/150 = Re ½

(i) C.P. of 4 oranges = 4 × ½ = Rs. 2

(ii) C.P. of 1 orange = Rs. ½ = Rs. (0.50)

(iii) S.P. of 1 orange Rs. ¾ = Rs. 0.75

(iv) Profit made by selling one orange

= Rs. ¾ - Rs. ½ = Rs. ¼ = Rs. 0.25

(v) If gain is Rs. ¼, number of oranges = 1

If gain is Rs. 24, number of oranges = 1/(1/4) × 24

= 1 × 4/1 × 24 = 96

Answered by Anonymous
1

Sell 5 oranges ------ rs. 4

orange ------- 4/5 rs - rs 0.8

Gain 40%

CP = (100/100+40)×0.8

= rs. 0. 75

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