Math, asked by maroof27, 1 year ago

a fruitseller bought 26 dozen orangs at the rate of ₹75 per dozen.Out of all oranges, 29 oranges were spoiled and sold the remaining at ₹1415. Determine. (a) the selling price of 1 orange (b) the total profit or loss percent

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Answered by skishankrishna
1

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maroof27: thanks
Answered by Strangercitizen1525
1

Oranges purchased=26 dozen.

Price per dozen= 75 Rs.

Total cost price= 26 * 75= 1950 rs.

cost of one orange =  6.25 rs.

Oranges spoiled=29

Oranges remaining= 312 - 29 = 283

Total number of oranges= 283

Total selling price= 1415 rs/-

a) Selling price per orange=1415 / 283 = 5 rs.

b) s.p - c.p = 1415 - 1950= -535 rs.

   therefore, loss = 535 rs.

loss percentage = ( loss *100)/c.p

                           = ( 535 * 100)/1950

                          = 27.5 percentage





maroof27: thanks
Strangercitizen1525: ur wlcm
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