Math, asked by avanibnair6, 19 days ago

A fruitseller buys 50 dozens of bananas for $3000. On the first day, he sells 30 dozens of bananas for a profit of 20%. The next day, he sells the remaining 20 dozens of bananas to an orphanage for a loss of 25%. What is the percentage profit/oss he got in this overall transaction?​

Answers

Answered by Harshit0115
0

Step-by-step explanation:

Cost For 50 Dozens Of Banana=$3000

Cost For 1 Dozen Of Banana=$3000

50

3000 \div 50 = 60

Cost For 1 Dozen Of Banana=$60

Cost Price For 30 Dozens Of Banana=$60*30

60 \times 30  = 1800

Cost Price For 30 Dozens Of Banana=$1800

Profit=20%

Selling Price For 30 Dozens Of Banana=Cost Price+Profit%orCost Price-Loss%

=$1800+20%

=$2160

Now,

Cost Price For 20 Dozens Of Banana=$60*20

60 \times 20 = 1200

Cost Price For 20 Dozens Of Banana=$1200

Selling Price For 20 Dozens Of Banana=Cost Price+Profit%orCost Price-Loss%

=$1200-25%

=900

Now,

Total Cost Price For 50 Dozens Of Banana=$(1800+1200)

=$3000

Total Selling Price For 50 Dozens Of Banana=$(2160+900)

=$3060

Profit=Selling Price - Cost Price

=$(3060-3000)

=$60

Profut%= Profit. x 100

Cost Price

=60 x 100

3000

=0.2% Profit

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Answered by Rejeet
0

Answer:- 2%

Step-by-step explanation:

first found cp of 1 dozen then added two sp of each profit and loss and sum total it. then found sp of 1 dozen and subtract to found profit then profit percent. hope the pic helps u..

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