A fruitseller buys 50 dozens of bananas for $3000. On the first day, he sells 30 dozens of bananas for a profit of 20%. The next day, he sells the remaining 20 dozens of bananas to an orphanage for a loss of 25%. What is the percentage profit/oss he got in this overall transaction?
Answers
Step-by-step explanation:
Cost For 50 Dozens Of Banana=$3000
Cost For 1 Dozen Of Banana=$3000
50
Cost For 1 Dozen Of Banana=$60
Cost Price For 30 Dozens Of Banana=$60*30
Cost Price For 30 Dozens Of Banana=$1800
Profit=20%
Selling Price For 30 Dozens Of Banana=Cost Price+Profit%orCost Price-Loss%
=$1800+20%
=$2160
Now,
Cost Price For 20 Dozens Of Banana=$60*20
Cost Price For 20 Dozens Of Banana=$1200
Selling Price For 20 Dozens Of Banana=Cost Price+Profit%orCost Price-Loss%
=$1200-25%
=900
Now,
Total Cost Price For 50 Dozens Of Banana=$(1800+1200)
=$3000
Total Selling Price For 50 Dozens Of Banana=$(2160+900)
=$3060
Profit=Selling Price - Cost Price
=$(3060-3000)
=$60
Profut%= Profit. x 100
Cost Price
=60 x 100
3000
=0.2% Profit
Please Mark Me Brainliest
Answer:- 2%
Step-by-step explanation:
first found cp of 1 dozen then added two sp of each profit and loss and sum total it. then found sp of 1 dozen and subtract to found profit then profit percent. hope the pic helps u..