Question

A fruitseller buys some oranges at the rate of 4 for a rupee and an equal number at 5 for a rupee. He sells the whole lot at 9 for two rupees . Find his gain or loss percent

Answer 1

let no of oranges be x
...
4 oranges=1 rupee
1 orange=1/4 rupee
x oranges=x/4 rupee
similarly..
another x oranges=x/5 rupee
total cp of 2x oranges=x/4+x/5=9x/20
now...
for sp:
9 oranges=2 rupees
1 orange=2/9 rupees
2x oranges=2/9*2x=4x/9 rupees
.....
loss=9x/20-4x/9=x/180.....
.....
loss%=x/180*20/9x*100%=1.12% loss

Answer 2

Answer:

Step-by-step explanation:

4orange-----------1Rs

=>1 orange------1/4Rs-------(1)

5oranges---------1Rs

=>1 orange------1/5Rs-------(2)

CP=1/4+1/5=9/20

Now Let we have only 2 oranges

9 orange---------2Rs

1 orange-----------2/9Rs

Now we know that we have two orange so,

2/9*2=4/9=SP

Now,CP-SP=9/20-4/9=>1/180

Loss%=(1/180)/(9/20)* =>(20/180*9)*

=1.23%