Question

a frustum of a right circular cone has a diameter of base of 14 cm and top 56 cm and height 45cm . find the volume of frustum.​

Answer 1

$\Large{\underline{\sf{\purple{Given}}}}$

• Height of frustum = 45 cm

• Base diameter = 14 cm

• Top diameter = 56 cm .

$\Large{\underline{\sf{\purple{To\:Find}}}}$

• Volume of frustum .

$\Large{\underline{\sf{\purple{Solution}}}}$

Formula of Volume of frustum is :-

$\large {\underline{ \underline{ \sf{ \implies \: \frac{\pi \: h}{3} ( {r}^{2} + R^{2} + rR)}}}}$

• ${\underline{\underline{\sf{r = \frac{14}{2} = 7 \: cm}}}}$

• ${\underline{\underline{\sf{R = \frac{56}{2} = 28 \: cm}}}}$

• ${\underline{\underline{\sf{h = 56 \: cm}}}}$

${\underline{ \underline{ \sf{ \implies \: \frac{\pi \times 56}{3} ( {(7)}^{2} + {(28)}^{2} + 7 \times 28 )}}}}$

$\sf{ \implies \: \frac{22 \times 56}{7 \times 3} (49 + 784 + 196) }$

$\sf{ \implies \: \frac{22 \times 8}{ 3} (49 + 784 + 196) }$

$\sf{ \implies \: \frac{22 \times 8}{ 3} (929) }$

$\sf{ \implies \: \frac{20438 \times 8}{ 3} }$

$\sf{ \implies \: \frac{163504}{ 3} }$

$\sf{ \implies \: 54501.34}$

$\large{\underline{ \underline{ \sf{ \implies \: volume \: is \: 54501.34 \: {cm}^{3} }}}}$

Answer 2

Answer:

refers to the attachment