Question

a frustum of cone has height 45 cm, radii of bases as 28 cm and 7 cm find the value of the frustum​

Answer 1

Given:-

• A frustum of cone has height 45 cm, radii of bases are 28 cm and 7 cm.

To Find:-

• Volume of the Frustum

Formula Used:-

• ${\boxed{\bf{Volume\:of\:Frustum\:of\:Cone=\dfrac{1}{3}\pi[R^2+r^2+R\times r]h}}}$

Solution:-

Using Formula,

$\bf :\implies\:Volume\:of\:Frustum\:of\:Cone=\dfrac{1}{3}\pi[R^2+r^2+R\times r]h$

Here,

• R = 28cm

• r = 7cm

• h = 45cm

Putting values,

$\sf :\implies\:Volume=\dfrac{1}{3}\times\dfrac{22}{7}\times[28^2+7^2+28\times 7]45$

$\sf :\implies\:Volume=\dfrac{1}{3}\times\dfrac{22}{7}\times 1,029\times45$

$\sf :\implies\:Volume=\dfrac{10,18,710}{21}$

$\bf :\implies\:Volume=48,510\:cm^3$

Hence, The Volume of Frustum of Cone is 48,510cm³.

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