a frustum of cone has radii of 2 circular ends are 7cm and 4.2cm if it's depth is 14 cm what is it's volume?
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R=7cm
r=4.2cm
h=14cm
volume=1/3πh(R²+r²+Rr)
=1/3×22/7×14[(7)²+(4.2)²+7×4.2]
=1/3×22×2[49+17.64+29.4]
=1/3×22×2×96.04
=1/3×22×2×9604/100
=422576/3×100
=140858.667/100
=1408.58667
=1408.59cm³
hope this answer will help you.
r=4.2cm
h=14cm
volume=1/3πh(R²+r²+Rr)
=1/3×22/7×14[(7)²+(4.2)²+7×4.2]
=1/3×22×2[49+17.64+29.4]
=1/3×22×2×96.04
=1/3×22×2×9604/100
=422576/3×100
=140858.667/100
=1408.58667
=1408.59cm³
hope this answer will help you.
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