Question

A fuel dealer mixes two brands of fuel which cost in the ratio 2:3. a solution containing 30% brand a and remaining brand b yields profit of 10% when sold at rs 297. what is cost of brand b?

Answer 1

270×10/100=27
270+27=297 so you got the cost price now
270/10=27
now brand b is 70% so 27×7= 189
189 is the cost price of brand b oil
and 27×3=81 is cost price of brand a


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Answer 2

Answer:

The cost of Brand B is 300

Step-by-step explanation:

Let quantity of solution sold be 1 litre

When the solution is sold for 297, the profit percent = 10%

Hence CP of of solution = SP × 100/(100+P%)

⇒CP = 297 × 100/(100+10)

⇒CP = 270

Ratio of quantities of brand A and brand B is 3:7

Let their costs be 2c and 3c.

⇒ 0.3×2c + 0.7×3c = 270

⇒ 2.7c = 270

⇒ c = 100

Hence cost of Brand B = 3c = 300

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