Physics, asked by chowdarypulipatipard, 4 months ago

A fully drunk drunkard, walks 4 steps forward and 1 step backward. Each step is of 1 feet and takes 1 second. There is a hole on the ground 6 feet ahead. How long will it take for drunkard to fall in the hole ?​

Answers

Answered by eshwanth200844
0

Explanation:

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Answered by Georik2020
0

Answer:

6 seconds.

Explanation:

The Drunkard walks four steps forward and one step backward. This means that the person is walking 3 feet in 3 seconds.

Thus, his speed (or, velocity) = 1 foot/second.

Thus, by Unitary Method:

The person walks 1 foot in 1 second.

⇒ The person would walk 6 feet in (1 x 6) = 6 seconds.

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