A fully drunk drunkard, walks 4 steps forward and 1 step backward. Each step is of 1 feet and takes 1 second. There is a hole on the ground 6 feet ahead. How long will it take for drunkard to fall in the hole ?
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Answer:
6 seconds.
Explanation:
The Drunkard walks four steps forward and one step backward. This means that the person is walking 3 feet in 3 seconds.
Thus, his speed (or, velocity) = 1 foot/second.
Thus, by Unitary Method:
The person walks 1 foot in 1 second.
⇒ The person would walk 6 feet in (1 x 6) = 6 seconds.
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