Math, asked by manan1318, 10 months ago

A fully filled rectangular tank have the following dimensions: length 4 meters, width 3 meters, and height 8 meters. The water in the tank is poured out from two holes simultaneously. From the first hole it pours at a rate of 2 cubic meters per second, and from the second one 3 cubic meters per second. How much will be the height in meters of the water after 6 seconds?

Answers

Answered by TheLightningWizard
0

Answer:

here is your answer ,grab it.

Step-by-step explanation:

Given-

capacity of the first hole-2m^3

capacity of second hole-3m^3

now we have to find the volume of the tank-

4 * 3* 8 = 96m^3

now we have to find the water released by the holes in 6 sec

2*6=12m^3

3*6=18m^3

total water lost=

12+18

30m^3

total loss in volume is equal to 96-30

=66 cubic metre

now find the decrease in height

let the height be x

4 * 3* x=66

12x=66

x=5.5m

so the height of water after 6 seconds will be 5.5 metres

____________thanks____________

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