A function f from N to N defined by f(n)- 2n+5 for all n€N is
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Answered by
0
Step-by-step explanation:
f(n)=2n+3 is a linear function.
Hence f(n
1
)=f(n
2
)⇒n
1
=n
2
Here Domain is N but range is set of all odd number −{1,3}
Hence f(n) is injective or one-to-one function.
Answered by
0
Answer:
f(n) is injective or one to one function.
Step-by-step explanation:
Given f: N→ N ( N is the set of natural numbers)
and f(n) = 2n + 5 for all n ∈ N
f(n) = 2n + 5 is a linear function
Hence f(n1) = f(n2)
⇒ n1 = n2.
Here Domain is N but range is set of all odd number -{ 1, 5}
Hence, f(n) is injective or one to one function.
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