Question

A function f is defined by f(x)=2x-3. (i)find f(0)+f(1)÷2

Answer 1

Step-by-step explanation:

f(x)=2x-3

solution:-

take value of x 0,1

f(0)+f(1)=

= 2(0)-3+2(1)-3

= 0-3+2-3

=-6+2

f(0)+f(1)=-4

f(0)+f(1)/2 = -4/2

= -2

i hope this answer will help u

Answer 2

The function value is $f(0)+f(1)\div 2=-3.5$

Step-by-step explanation:

Given : A function f is defined by $f(x)=2x-3$

To find : Expression $f(0)+f(1)\div 2$ ?

Solution :

Function $f(x)=2x-3$

Put x=0,

$f(0)=2(0)-3$

$f(0)=-3$

Put x=1,

$f(1)=2(1)-3$

$f(1)=-1$

Substitute in the expression,

$f(0)+f(1)\div 2=-3+(-1)\div 2$

$f(0)+f(1)\div 2=-3-\frac{1}{2}$

$f(0)+f(1)\div 2=\frac{-6-1}{2}$

$f(0)+f(1)\div 2=\frac{-7}{2}$

$f(0)+f(1)\div 2=-3.5$

Therefore, the function value is $f(0)+f(1)\div 2=-3.5$

#Learn more

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