A function f:R-->R is defined as
f (x+1)= f(x) + 2x +3, f (0)=1 .
Find f (2020).
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Step-by-step explanation:
What I did:
f(2x+3)+f(2x+7)=2.........(1)
Replacing x with x−1 in (1),
f(2x+1)+f(2x+5)=2.........(2)
And replacing x with x+1 in (1),
f(2x+5)+f(2x+9)=2.........(3)
Subtracting (2) from (3), I get
f(2x+1)=f(2x+9)
Since x∈R⟺2x∈R, replace 2x with x to get
f(x)=f(x+8)⟹t=8
But sadly, my textbook's answer is t=4.
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