Question

A function f:R→R is defined as f(n+1) = f(x) +2x+3 ,f(0)=1
find f(2020) =?​

Answer 1

Answer:

(2021)^2 is the answer

Step-by-step explanation:

when x=0, then f(1)=4

x=1,then f(2)=9

x=2,then f(3)=16

you can look at the pattern

when f(1)=2^2

As you can see here f(1)= (1+1)^2

f(2)=3^2

As you can see here f(2)= (2+1)^2

like wise for f(2020)= (2021)^2

Answer 2

Answer:

I think there's some calcultion mistake if the answer is wrong but the procedure is perfect