A function f : R → R is defined as f(x) = 3 − || Show that f(x) is not surjective.
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Answer:
one−one test for f:
Let x and y be two elements of domain (R), such that
⇒ f(x)=f(y)
⇒ x
3
+4=y
3
+4
⇒ x
3
=y
3
⇒ x=y
∴ f is one-one.
onto test for f:
Lety be in the co-domain (R), such that,
⇒ f(x)=y
⇒ x
2
+4=y
⇒ x=
3
y−4
∈R (Domain)
∴ f is onto.
Since, f is one-one and onto then it is bijective.
∴ f is invertible.
Find f
−1
:
Let f
−1
(x)=y ----- ( 1 )
⇒ x=f(y)
⇒ x=y
3
+4
⇒ x−4=y
3
⇒ y=
3
x−4
From ( 1 ),
⇒ f
−1
(x)=
3
x−4
⇒ f
−1
(3)=
3
3−4
=
3
−1
=−1
Step-by-step explanation:
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