a function f: R-R is Defined by F(x)=2x^2 is the function f is one one and onto justify your answer?
Answers
Answered by
4
funtion is not one one and onto.
range of the function [ 0, ∞)
so function is into and
at
x = 1 & x = -1
y = 2 ( which gives same value )
so funtion is not one - one.
now we can say that function is many one & into.
———————————————
Hope it will help you.✌✌
range of the function [ 0, ∞)
so function is into and
at
x = 1 & x = -1
y = 2 ( which gives same value )
so funtion is not one - one.
now we can say that function is many one & into.
———————————————
Hope it will help you.✌✌
Ankursaikia:
brefly description
Answered by
0
Answer:
The function is not one one but onto.
Step-by-step explanation:
check one one :
f(x1) = f(x2)
=>2x²1 = 2x²2
=>x1 = ±x2
Thus , the function f is not one one .
check onto :
f(x) = 2x²
=> y = 2x²
=> x = √y/2
Therefore , f(√y/2) = 2(√y/2)² = y
=> f(x) = y
Thus , the function is onto.
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