Math, asked by guptasakshi9550, 11 months ago

A function y = f(x) has a second order derivative f "(x) = 6(x -1). If its graph passes through the point (2,1) and at that point the tangent to the graph is y = 3x – 5, then the function is
(a) (x +1)²
(b) (x -1)³
(c) (x +1)³
(d) (x -1)²

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Answered by Priyangshukar

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