a funnel can discharge a tank in 40 minutes. a second pipe with distance across twice as much as that of the first is likewise joined with the tank to purge it. the two together can exhaust the tank in? answer
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first pipe that can empty a tank in 40 minutes has radius 'r', its 1 min. empty rate=1/40
As the second pipe has double the diameter than first will have radius=2r, so its flow will be directly proportional to cross sectional area=Pi*(2r)^2=4*Pi*r^2, which is 4 times the first pipe.
So the empty rate of second pipe=4/40=1/10
So together both pipes can empty the tank in 1/[(1/40)+(1/10)]=8 min.
As the second pipe has double the diameter than first will have radius=2r, so its flow will be directly proportional to cross sectional area=Pi*(2r)^2=4*Pi*r^2, which is 4 times the first pipe.
So the empty rate of second pipe=4/40=1/10
So together both pipes can empty the tank in 1/[(1/40)+(1/10)]=8 min.
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