Question

a furniture dealer earn profit of rupees 500 by selling a table and loss of rupees 150 by selling a chair (a) he sold 20 tables and 20 chairs what would be his net profit or loss ? (b) what is number of tables he must sell to have neither profit nor loss to have if the number of chairs sold is 60

Answer 1

a) his net profit would be 7000(profit for table 10000 loss for chair 3000=150*20)
b) 60chair price is 60*150=900 which is equal to 500*18 therefore the no of table he sold is 18

Answer 2

Answer:

(a) Net profit  = 7000

(b) Number of tables he must sell to have neither profit nor loss = 18

Step-by-step explanation:

Given,

Profit of selling a table = 500

Loss of selling a chair = 150

(a)

To find,

Net profit of selling 20 tables and chairs

Profit of selling 20 tables = 500×20 = 10000

Loss of selling 20 chairs = 150 ×20 = 3000

Since the profit of selling tables is greater than the loss of selling chairs, there is a net profit

Net profit = 10000 - 3000 = 7000

(b)

Given,

The number of chairs sold is 60

To find,

No. of tables he must sell such the net profit/loss is zero

Solution

Let 'n' be the number of tables required to sell

Profit of selling 'n' tables =  500n

Loss of selling 60 chairs  = 150 ×60 = 9000

net profit/loss  =  500n - 9000

Given that the net profit/loss = 0

that is 500n - 9000 = 0

500n = 9000

n = 18

∴ Number of tables he must sell to have neither profit nor loss = 18

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