Question

A furniture shop owner bought 236 chairs and 8 tables for $9548.Each chair cost $25. How much did each table cost?​

Answer 1

Answer:

let x be chairs

and y be tables

using algebra

$236x + 8y = 9548 \\ 236(25) + 8y = 9548 \\ 8y = 3648 \\ y = 456$

hence each table costs "$456"

Answer 2

Answer

Cost of one chair =  $25

Total chairs = 236

Cost of 236 chairs= $25*236    = $ 5900

Total costs of  236 chairs and 8 tables = $ 9548

Cost of 8 tables = $9548 -$5900    = $3648

Cost of one table= $3648 divided by 8

                          =$456