Physics, asked by chandankkbharad5469, 9 months ago

A fuse wire with a radius of 1 mm blows at 1.5 A. If the fuse
wire of the same material should blow at 3.0 A, the radius of
the wire must be
(a) 4¹/³ mm (b) √2 mm
(c) 0.5 mm (d) 8.0 mm

Answers

Answered by Anonymous
0

Answer:

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Explanation:

Given :

Radius of first wire = 1mm

Current blow in first wire = 3A

Radius of second wire = 2mm

To Find :

Current blow in second wire = ?

Concept :

Here both wire has same lenght and made up from same material therefore resistivity of both wires is also same...

Formula :

As per ohm's law V=IR

......................................................................................

We know that

......................................................................................

Calculation :

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