Math, asked by lalitkumar8055, 10 months ago

[A] g'(π/2) = -2π [B] g'(-(π/2)) = 2π
[C] g'(π/2) = 2π [D] g'(-(π/2)) = -2π

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Answered by Anonymous

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i think

[B] g'(-(π/2)) = 2π

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