Math, asked by narenv844, 4 months ago

a G.P. 729, 243, 81 ... find t7.
20. Find the sum of 13 + 23 + 33 +43 +
+ 703
21 Find the zeros of the 1​

Answers

Answered by zarathequeen
26

Step-by-step explanation:

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Attachments:
Answered by mss0144
1

Answer:

hey dear

Step-by-step explanation:

It is given that the first term of G.P is a1=729 and the second term is a2 =243, therefore,

r= a2/a1= 243/729= 1/3

We know that the formula for the nth term of an G.P is Tn=ar^n−1 , where a is the first term, r is the common ratio.

It is given that the first term is a=729 and the common ratio is r= 1/3

, thus,

T7=729×( 1/3)^7−1 =729×1/3^6

=729/729 =1

Hence, T7=1

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