A GaAs Laser operating at 850nm has 250µm length and a refractive index of 3.7.What are the frequency and wavelength spacing?
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Given: λ= 850nm, L= 250µm, n= 3.7
To find: Frequency spacing and wavelength spacing
Solution: The frequency spacing Δf of standing waves is written as
Δf = c/2Ln
where c is speed of light ,n is the index of refraction, L is cavity length
Similarly, The wavelength spacing Δλ of standing waves can be written as
Δλ= λ2/2Ln
where λ is the wavelength
now putting the values L, n, λ and c= 3×10^8
Δf = c/2Ln
Δf = 3×10^8/ 2× 250×10^-6× 3.7
Δf = 81.0810GHz
Δλ= λ2/2Ln
Δλ= (850×10^-9)^2/ 2× 250×10^-6× 3.7
Δλ= 195.2702 pm
Therefore the value of Frequency spacing Δf = 81.0810GHz and wavelength spacing Δλ= 195.2702 pm.
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