Chemistry, asked by naincysharma047, 3 months ago

a galvanic cell consists of a metalic zinc plate immersed in 0.1 M zinc nitrate solution calculate the emf of the cell at 25°c. write the chemical equations for the electrode reactions.

Answers

Answered by ItzTwinklingStar

Answer:

-So at anode zinc undergoes oxidation by losing two electrons and lead undergoes reduction by accepting two electrons. The emf of the cell at 25∘C is 0.6093volt.

Attachments:

Previous Question

Next Question

Similar questions

Math, 1 month ago

Find the least number of 4 digits which is a perfect square.

Social Sciences, 1 month ago

write about air,water resources. $585666256665$ ...

Math, 1 month ago

If p, q, r greater than or equal to 4 are integers are integers , not all equal and 4pgr = (p+3) (q+3) (r+3) then the value of p + q+r is...

Physics, 3 months ago

Specify the electrodes that belong to the class of electrodes for dynamic monitoring of the patient's condition...

Math, 3 months ago

2×3435+477889+22903 ...

English, 9 months ago

My Father's, bother is my......

Math, 9 months ago

.Find three irrational numbers between 5/7and 9/11...

Science, 9 months ago

please answer this question...

a galvanic cell consists of a metalic zinc plate immersed in 0.1 M zinc nitrate solution calculate the emf of the cell at 25°c. write the chemical equations for the electrode reactions.​

Answers

a galvanic cell consists of a metalic zinc plate immersed in 0.1 M zinc nitrate solution calculate the emf of the cell at 25°c. write the chemical equations for the electrode reactions.