a galvanic cell is set up from a zinc bar weighing 100g and 1 litre of 1M CuSO4 solution. How long the cell would run if it is assumed to deliver a steady current of 1 amp
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Answered by
3
Hi friend
Hope this helps you
The answer is 53.6 hr.,
Hope this helps you
The answer is 53.6 hr.,
shradha1008:
plz provide solution
Answered by
40
Hey dear,
● Answer -
t = 53.6 hr
● Explanation -
Moles of zinc reduced
= 100/65
= 1.53 mol
Here, CuSO4 is limiting reagent.
Cu2+ + 2e- ---> Cu
That is to completely dissolve 1 mol of Cu, 2 moles of electrons are required.
Time for which cell runs is -
t = Q / I
t = 2 × 96500 / 1
t = 193000 s
t = 53.61 hrs
Therefore, cell will run for 53.61 hrs.
Hope this helps you...
● Answer -
t = 53.6 hr
● Explanation -
Moles of zinc reduced
= 100/65
= 1.53 mol
Here, CuSO4 is limiting reagent.
Cu2+ + 2e- ---> Cu
That is to completely dissolve 1 mol of Cu, 2 moles of electrons are required.
Time for which cell runs is -
t = Q / I
t = 2 × 96500 / 1
t = 193000 s
t = 53.61 hrs
Therefore, cell will run for 53.61 hrs.
Hope this helps you...
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