Question

A galvanic is obtained by the combination of iron rod immersed in iron sulphate solution of concentration 0.35M and copper rod immersed in copper sulphate of concentration 0.5M. given cell representation,cell reactions of calculate EMF of the cell at 29degree celcius given the standard potential of Cu and Fe electrode are 0.34 and -0.41V respectively.​

Answer 1

Answer:

Given Zn∣Zn  

2+

(0.001M)∣∣Cu  

2+

(0.1M)∣Cu

Overall cell reaction:

Zn⟶Zn  

2+

+2e  

−

 

Cu  

2+

+2e  

−

⟶Cu

​  

 

Zn+Cu  

2+

⟶Zn  

2+

+Cu

​  

 

E  

cell

o

​  

=standard reduction potential of cathode + standard oxidation potential of anode

E  

cell

o

​  

=0.34 to 0.76 V

E  

cell

o

​  

=1.1 V

K  

C

​  

=  

[Cu  

2+

]

[Zn  

2+

]

​  

=  

10  

−1

 

10  

−3

 

​  

=10  

−2

 

EMF of the cell at any electrode concentration is:

E=E  

o

−  

n

0.059

​  

log(K  

C

​  

)=1.1−  

2

0.059

​  

log(10  

−2

)=1.1−  

2

0.059

​  

×(2)=1.1−0.059=1.041V

Explanation: