A galvanometer coil has a resistance G. 1% of the total current goes through the coil and rest through the shunt. What is the resistance of the shunt?
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Answer:
Rₙ = G/99
Explanation:
If 1% current passes through the galvanometer of resistance G, 99% of current passes through shunt.
0.01I × G = 0.99I × Rₙ {Here I am using n in place of S}
Rₙ = G/99
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