Question

a galvanometer coil of resistance 12ohm gives full scale division for 3mA.How will you convert it into a voltmeter of range 0 to 18 V and ammeter of range 0 to 6А​

Answer 1

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Question :- A galvanometer coil has of resistance 12ohm gives full deflection of current of 3mA . How will you convert it into a voltmeter of range 0 to 18v and ammeter of range 0 to 6A ??

Answer :-

For converting into voltmeter.

Given :-

G = 12 , V = 18

$ig= 3 \times 10 { }^{ - 3}$

FORMULA USED :-

R = V/Ig - G

Solutions :-

R = 18 / 3 ×10^-3 -- 12

R = 5988 ohm

For converting into Ammeter.

Given :-

G = 12 , V = 18

$ig= 3 \times 10 { }^{ - 3}$

FORMULA USED :-

S = Ig G / I - Ig

Solutions :-

S = 3 × 10^-3 × 12 / 6 - 3 × 10^-3

S = 36 / 5997 ohm

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