Question

a galvanometer has 36 ohm resistance lf a 4 ohm shunt is added to this ,the fraction of current that passes through the galvanometer is:-1)1/42)1/93)1/404)1/10

Answer 1

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Answer is in pic below

Answer 2

Answer:

(4). The friction of current that passes through the galvanometer is $\dfrac{I_{g}}{i}=\dfrac{1}{10}$.

Explanation:

Given that,

Galvanometer G =36 ohm

Shunt S = 4 ohm

The formula for ammeter

$I_{g}G=(i-I_{g})S$

Here, $I_{g}$= galvanometer current

G = galvanometer

S= shunt

i = current

$\dfrac{G}{S}=\dfrac{i-I_{g}}{I_{g}}$

$\dfrac{36}{4}=\dfrac{i}{I_{g}}-1$

$9+1=\dfrac{i}{I_{g}}$

$\dfrac{I_{g}}{i}=\dfrac{1}{10}$

Hence, The friction of current that passes through the galvanometer is $\dfrac{I_{g}}{i}=\dfrac{1}{10}$.