Physics, asked by achhi1121, 11 months ago

A galvanometer has a resistance of 15ohm and the meter shows full scale deflection for the current of 4ma how will you conevet the meter into ammeter of range 0 to 6a

Answers

Answered by rishabh2328
0

\bold\red{ANSWER!}

To converts galvanometer into ammeter of required range , we should join join shunt in parallel combination with galvanometer metre.

Let G is the resistance of galvanometer.

S is the resistance of shunt join in parallel with galvanometer.

I_gI

g

is the current passing through galvanometer. and I is the maximum range of current.

now, S=\frac{I_gG}{I-I_g}S=

I−I

g

I

g

G

here, Ig = 4mA = 4 × 10^-3A

I = 6A , G = 15 ohm

now, S=\frac{4\times10^{-3}\times15}{6-4\times10^{-3}}=0.01\OmegaS=

6−4×10

−3

4×10

−3

×15

=0.01Ω

Answered by Anonymous
3

Answer:

Refer the attached picture.

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