a galvanometer has a resistance of 25 ohm and it's full scale deflection current is 25um what resistance should be added to it to have a range of 0-10v?
Answers
Answer:
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Explanation:
formula : S= G*I/ (I-Ig)
where S= shunt resistance , (I-Ig)= current through the shunt resistance , I=Current in the circuit.
Here, galvanometer resistance ,G= 25 ohm ; Ig= 0.001 A , I= 2A
S= (25* 0.001 )/( 2- 0.001)
= 1.25×10 −3Ω
A shunt resistance of 1.25×10−2Ω must be connected to make the galvanometer in the range of 0 to 2A
Concept:
Resistance is a unit of measurement for the restriction of current flow in an electrical circuit. Ohms is the SI unit is used to measure resistance. The resistance can be calculated by the formula, R = V/Ig - G
Given:
Resistance of galvanometer, G = 25ohm
Current, Ig = 25 μA = 25 × 10^-6 A
Maximum voltage, V = 10V
Find:
We need to determine the resistance, R that should be added to have a range of 0-10 V
Solution:
The ratio of the potential difference across a conductor's end to the current passing through it is known as the conductor's resistance. The ohm is its SI unit.
Resistance can be calculated by the formula-
R = V/Ig - G where V = Maximum voltage, Ig = deflection Current and G = Resistance of galvanometer and R = resistance
It has been given that V = 10V, G = 25 ohm and Ig = 25 × 10^-6 A
Therefore, equation of resistance becomes,
R = 10/25 × 10^-6 - 25
R = 4,00,000 - 25
R = 3,99,975 ohms
R = 399.975 × 10³ ohms
Thus, the resistance that should be added to the galvanometer to have a range of 0-10 V is 399.975 × 10³ ohms.
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