A galvanometer has a resistance of 30 ohm it gives full scale deflection with a current
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Question. A galvanometer has a resistance of 30 ohm . it gives full scale deflection with a current of 2ma.calculate the value of the resistance neededto convert it into an ameter 0-0.3A?
Ans.
V=IR
V=0.3 * R
Ig = V/G+R
Ig(G+R) = V
R= (V/Ig) - G
R=( 0.3R/2*10-3)-30
By taking LCM
R(2*10-3) = 0.3R - 30* (2 * 10-3)
R(2*10-3-0.3)= -30 * (2*10-3 )
R(-298 * 10-3) = -60 * 10-3
298R = 60
R = 60/298
R = 0.2013 ohms
Ans.
V=IR
V=0.3 * R
Ig = V/G+R
Ig(G+R) = V
R= (V/Ig) - G
R=( 0.3R/2*10-3)-30
By taking LCM
R(2*10-3) = 0.3R - 30* (2 * 10-3)
R(2*10-3-0.3)= -30 * (2*10-3 )
R(-298 * 10-3) = -60 * 10-3
298R = 60
R = 60/298
R = 0.2013 ohms
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