Physics, asked by skcom1976, 9 months ago

a galvanometer has a resistance of 40 ohm.it shows full scale defection for a current of 2 mA.how will you convert the galvanometer into a voltmeter if range 0 to 20 v

Answers

Answered by bookbug28
0

Answer:

Add a resistance 9969ohm in series

Explanation:

We have galvanometer resistance, G=40 ohm.

Galvanometer current Ig= 2mA

Max voltage =20V

From the formula,

Ig(G+R) = V ,

where R is unknown resistance,

We get,

40+R = 20÷2×10^-3

= 10^4

R = 9960 ohm

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