a galvanometer has a resistance of 40 ohm.it shows full scale defection for a current of 2 mA.how will you convert the galvanometer into a voltmeter if range 0 to 20 v
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Answer:
Add a resistance 9969ohm in series
Explanation:
We have galvanometer resistance, G=40 ohm.
Galvanometer current Ig= 2mA
Max voltage =20V
From the formula,
Ig(G+R) = V ,
where R is unknown resistance,
We get,
40+R = 20÷2×10^-3
= 10^4
R = 9960 ohm
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