A galvanometer has a resistance of 40 ohms and a current of 4mA is needed for a full scale deflection. What is the resistance and how is it to be connected to convert the galvanometer
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Given info : A galvanometer has a resistance of 40 ohms and a current of 4mA is needed for a full scale deflection.
To find : what is the resistance and how is it to be connected to convert the galvanometer
- into an ammeter with a range of 0.3 A
- into a voltmeter with a range of 0.2 volts.
solution : 1. to convert the galvanometer into an ammeter, we should connect a resistance (shunt) in parallel with it.
here resistance of Galvanometer, G = 40 ohm
resistance of shunt = S
current through the galvanometer, Ig = 4mA
I = 0.3 A
using formula, S = Ig × G/(I - Ig)
= 4 × 10¯³ × 40/(0.3 - 4 × 10¯³)
= 0.16/(0.3 - 0.004)
= 0.16/0.296
= 0.54 ohm
2. To convert the galvanometer into a voltmeter, we should connect a resistance in series combination with it.
here resistance is R
from Ohm's law, V = Ig(R + G)
here Ig = 4mA , G = 40 ohm, V = 0.2 volts
so, 0.2 = 4 × 10¯³(R + 40 )
⇒50 = R + 40
⇒R = 10 ohm
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