Question

A galvanometer has a resistance of 98 ohm. If 2% of main current is passed through the meter. find the value of shunt resistance?​

Answer 1

Answer:

s= 1.96 ohm

Explanation:

given: resistance(G)=98 ohm,current(i)=2%=0.02 c

shunt resistance(s)= i×G

=98×0.02=1.96 ohm

Answer 2

Answer:

G=98Ω,igi×100=2%

s=G(iig−1),∴iig=1002=50∴S=98(50−1)=2Ω

Explanation: