Physics, asked by MrAmazing2224, 8 months ago

A galvanometer has resistance G and shows full scale deflection for current Ig.
i. How can it be converted into an ammeter to measure current up to I0 (I0 > Ig)?
ii. What is the effective resistance of this ammeter?​

Answers

Answered by akashripu
8

Answer

if you want to convert galvanometer into ammeter you have to add the shunt in parallel with the galvanometer. as you may know the shunt is the wire with very low resistance. so  maximum current will pass through the shunt and you can measure the required amount of current.

the effective resistance of the circuit will be Rs+Rg/RsRg.

hope this helps mate

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