Question

A galvanometer having a coil resistance of 60 22
shows full scale deflection when a current of 1.0 A
passes through it. It can be converted into an ammeter
to read currents upto 5.0 A by

Answer 1

Answer:

So here given that Rm=20 ohm, Im=0.5A, I=5A, Rs=?

Rs=20/[(5/0.5) -1]

Rs=20/[10–1], => Rs = 20/9 = 2.22 ohm

So we need to connect a shunt resistance of 2.22 ohm in parallel to the existing 20 ohm , to make an ammeter of (0–5) A.

If any questions you have, feel free to comment.

Thanks & Regards

Deepak

mark me brailiest