A galvanometer having resistance of 10ohm is shunted by resistance 1 ohm, if total current is 2 A, then which part of total current passing through shunt
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Here, V
G
=V
S
so I
G
G=I
S
S
or (I−I
S
)G=I
S
S
or I
S
=
G+S
IG
=
8+2
1×8
=0.8A
I hope it will help you
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