A galvanometer of resistance 10 ohm gives full scale deflection for a current of 4mA . How can it converted into an ameter of range 0 to 5 A ?
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So when there is a 5 A current you need 4 mA (0.004 A) through the galvanometer’s 10 ohm coil and the rest 4.996 A tough the shunt R ohm. so you have equating the voltages across the parallel combination :
10 x 0.004 = R x 4.996 , yielding R to be 0.008006405124 or approximately 0.008 ohm.
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