Physics, asked by karthikthejendra, 11 months ago

A galvanometer of resistance 100ohm has 30 divisions. When a potential difference of 0.1V is applied to its terminals, it deflects by 10 divisions. How will you convert it into an ammeter to read upto 2A?

Answers

Answered by azizalasha
0

Answer:

solved

Explanation:

in parallel

200R /( R+100) = total voltage= 0.3

200R = 30 + 0.3R

R =  30/199.7

Similar questions