A galvanometer of resistance 100ohm has 30 divisions. When a potential difference of 0.1V is applied to its terminals, it deflects by 10 divisions. How will you convert it into an ammeter to read upto 2A?
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Explanation:
in parallel
200R /( R+100) = total voltage= 0.3
200R = 30 + 0.3R
R = 30/199.7
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