Question

A galvanometer of resistance 25 N measures
10^ 3 A. shunt required to increase range up to 2 A​

Answer 1

Answer:

where S= shunt resistance , (I-Ig)= current through the shunt resistance , I=Current in the circuit.

Here, galvanometer resistance ,G= 25 ohm ; Ig= 0.001 A , I= 2A

S= (25* 0.001 )/( 2- 0.001)

= 1.25×10

−3

Ω

A shunt resistance of 1.25×10

−2

Ω must be connected to make the galvanometer in the range of 0 to 2A

Answer 2

Answer:

The above attachment may help u