A galvanometer with a coil of resistance 12ohm shows a full scale deflection for a current 2.5ma how will you convert the meter into an ammeter of range 0 to 7.5 a voltmeter of range 0 to 10v
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Answer:
Given parameters:
I → Total current in circuit = 7.5 A
G → Resistance of the galvanometer = 12 Ω
Ig → Current through galvanometer = 2.5 × A
V → Potential difference across the terminals = 10 V
case 1: Conversion of a galvanometer to ammeter
A shunt (low resistance) is connected in parallel with the galvanometer.
calculate the value of shunt resistance from the above formula
case 2: Conversion of galvanometer to voltmeter
A high resistance is connected in series with the galvanometer.
Explanation:
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