a galvanometer with a coil of resistance 12ohm shows full scale deflection for a current of 2.5 mA . How will you convert it into a Voltmeter of range 7.5V ? Also find the total resistance of voltmeter formed.
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A galvanometer with a coil of resistance 120 ohm shows full scale deflection for a current of 2.5 mA. ... Galvanometer can be converted into an ammeter bu putting a shunt in parallel with galvanometer. Therefore, By connecting a shunt of 0.04 Ω across the given galvanometer, we get an ammeter of range of 0 to 7.5 A.
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The answer is s= 4*10^-3 ohms and R = 0.03 ohms
Explanation:
s = Ig *G / I - Ig
= 2.5*10^-3 *12 / 7.5 - 2.5*10^-3
= 0.03 / 7.4975
s = 4*10^-3 ohms
The required resistance is ...
R = 120*0.04 / 120+0.04
R = 0.03 ohms
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