Question

A game consists of tossing a one rupee coin 3 times and noting its outcome each time. Hanif wins if all the tosses give the same result i.e., three heads or three tails, and loses otherwise. Calculate the probability that Hanif will lose the game.​

Answer 1

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The total number of outcomes

= 8 (HHH, HHT, HTH, THH, TTH, HTT, THT, TTT)

Total outcomes in which Hanif will lose the game

= 6 (HHT, HTH, THH, TTH, HTT, THT)

P (losing the game)

=6/8

= ¾

= 0.75

Answer 2

$\huge\red{\underline{{\boxed{\textbf{QUESTION}}}}}$

A game consists of tossing a one rupee coin 3 times and noting its outcome each time. Hanif wins if all the tosses give the same result i.e., three heads or three tails, and loses otherwise. Calculate the probability that Hanif will lose the game.

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Total number of outcomes when a coin is tossed 3 times : 2*2*2 = 8

the two outcomes H or T for each toss is independent of other tosses. So they are multiplied.

Two outcomes give winning combination = 3 H or 3 T..

Hence probability of failure = (8-2)/8 = 3/4

__________________

@HarshPratapSingh