a game consists of tossing a one rupee coin 3 times and noting its outcomes each time.hanif wins if all the tosses give the same result I,e... 3 heads or 3 tails and loses otherwise.calculate the probability that hanif will lose the game.
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Answered by
506
possible outcomes of 3 times tossing a coin
1st= HHH
2nd= HHT or HTH or THH
3rd= TTHor THTor HTT
4th=TTT
Total number of events=8
No of favourable events=6(refer to 2nd and 3rd cases)
P(E)= 6/8=3/4
1st= HHH
2nd= HHT or HTH or THH
3rd= TTHor THTor HTT
4th=TTT
Total number of events=8
No of favourable events=6(refer to 2nd and 3rd cases)
P(E)= 6/8=3/4
Answered by
252
total number of outcomes when a coin is tossed 3 times : 2*2*2 = 8
the two outcomes H or T for each toss is independent of other tosses. So they are multiplied.
Two outcomes give winning combination = 3 H or 3 T..
Hence probability of failure = (8-2)/8 = 3/4
the two outcomes H or T for each toss is independent of other tosses. So they are multiplied.
Two outcomes give winning combination = 3 H or 3 T..
Hence probability of failure = (8-2)/8 = 3/4
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