Question

A game is biased such that the choices A-J have the following probabilities of winning: A 5% B 10% C 15% D 5% E 5% F 25% G 10% H 10% I 10% J 5% If you chose the letters D and H for 20 turns, how many times are you most likely to win?

Answer 1

To find your expected number of wins, multiply the probability of winning by the number of times played.

Together, D & H have a 15% chance of winning.

 

0.15 * 20 plays = 3 wins


plz mark as brainly...
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Answer 2

the game winning is 15%