Math, asked by alisha485, 1 year ago

A game of chance consists of spinning an arrow, which comes to rest
pointing at one of the numbers 1,2,3,4,5,6,7,8 and these are equally
likely outcomes. Find the probability that the arrow will point at any
factor of 8.​

Answers

Answered by mahesh1973goodu
3

Answer:

No. Of events = 1,2,3,4,5,6,7,8

Factors of 8 = 1, 2 , 4 and 8

Therefore, Probability =4/8

=1/2

Answered by Anonymous
0

Ans. Out of 8 numbers, an arrow can point any of the numbers in 8 ways.

Total number of favourable outcomes = 8

(i) Favourable number of outcomes = 1

Hence, P (arrow points at 8) =

(ii) Favourable number of outcomes = 4

Hence, P (arrow points at an odd number) =

(iii) Favourable number of outcomes = 6

Hence, P (arrow points at a number > 2) =

(iv) Favourable number of outcomes = 8

Hence, P (arrow points at a number < 9) = =1

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