Math, asked by patkarirekha, 11 months ago

A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5,
6, 7, 8 (See figure), and these are equally likely outcomes. What is the probability that it will point at (i) 8 ?(ii) an odd number ? (iii) a number greater than 2 ? (iv) a number less than 9?​

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Answered by Anonymous
34

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Answered by Anonymous
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Answer:

Ans. Out of 8 numbers, an arrow can point any of the numbers in 8 ways.

Total number of favourable outcomes = 8

(i) Favourable number of outcomes = 1

Hence, P (arrow points at 8) =

(ii) Favourable number of outcomes = 4

Hence, P (arrow points at an odd number) =

(iii) Favourable number of outcomes = 6

Hence, P (arrow points at a number > 2) =

(iv) Favourable number of outcomes = 8

Hence, P (arrow points at a number < 9) = =1

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