A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see the given figure), and these are equally likely outcomes. What is the probability that it will point at
(i) 8?
(ii) an odd number?
(iii) a number greater than 2?
(iv) a number less than 9?
Answers
Answered by
72
Hope this will help u.
Attachments:
Answered by
27
Total no of favourable outcomes =8
no of time 8 may come=1
⇒p(it will point at 8) =1/8
no of time an odd may come = 4 (1,3,5,7)
⇒P(getting odd no)=4/8 = 1/2
no of time getting a number greater than two =6 (3,4,5,6,7,8)
⇒p(getting a number greater than two)=6/8=3/4
a number less than 9 =8
⇒p(getting a number less than 8)=8/8=1
Similar questions